This equation shows how both enthalpy and entropy influence the spontaneity of a process.
At room temperature (298 K), ice melts spontaneously. Let's consider the thermodynamic values:
- \( \Delta H = +6.01 \, \text{kJ/mol} \)
- \( \Delta S = +22.0 \, \text{J/mol·K} \)
Convert \( \Delta S \) to kJ: \( 22.0 \, \text{J/mol·K} = 0.022 \, \text{kJ/mol·K} \)
\[
\Delta G = 6.01 - (298 \times 0.022) = 6.01 - 6.556 = -0.546 \, \text{kJ/mol}
\]
Conclusion: Since \( \Delta G < 0 \), melting is spontaneous at 298 K.
The thermal decomposition of calcium carbonate:
\[
\text{CaCO}_3 (s) \rightarrow \text{CaO} (s) + \text{CO}_2 (g)
\]
- \( \Delta H = +178 \, \text{kJ/mol} \)
- \( \Delta S = +160 \, \text{J/mol·K} = 0.160 \, \text{kJ/mol·K} \)
At 298 K:
\[
\Delta G = 178 - (298 \times 0.160) = 178 - 47.68 = 130.32 \, \text{kJ/mol}
\]
Conclusion: Since \( \Delta G > 0 \), this reaction is non-spontaneous at room temperature.